Rancho Santa Fe ITF 2016 (USA)
(25,000 $, hard, women)
Start | Round | S | 1 | 2 | 3 | 4 | 5 | H | A | ||
27.02. 22:45 |
F | Muhammad / Townsend (1) | 2 | 6 | 6 | 1.49 | 2.40 | info | |||
Pegula / Zhao (3) | 0 | 3 | 4 | ||||||||
27.02. 01:10 |
SF | Muhammad / Townsend (1) | 2 | 6 | 6 | 1.39 | 2.67 | info | |||
Bellis / Cako | 0 | 1 | 3 | ||||||||
26.02. 22:25 |
SF | Pegula / Zhao (3) | 2 | 6 | 3 | 14 | 1.50 | 2.38 | info | ||
Hibi / Min | 1 | 1 | 6 | 12 | |||||||
26.02. 02:20 |
QF | Pegula / Zhao (3) | 2 | 6 | 7 | 1.51 | 2.32 | info | |||
Burgic Bucko / Wong | 0 | 4 | 5 | ||||||||
26.02. 01:10 |
QF | Bellis / Cako | 2 | 7 | 6 | 1.52 | 2.34 | info | |||
Christian / Lao | 0 | 61 | 4 | ||||||||
26.02. 01:05 |
QF | Muhammad / Townsend (1) | 2 | 6 | 6 | 1.36 | 2.81 | info | |||
De Vroome / Sanchez-Q | 0 | 4 | 2 | ||||||||
25.02. 23:35 |
QF | Hibi / Min | 2 | 6 | 0 | 10 | 1.89 | 1.79 | info | ||
Kuwata / Okuno (2) | 1 | 3 | 6 | 8 | |||||||
25.02. 01:15 |
R16 | Burgic Bucko / Wong | 2 | 6 | 6 | 1.27 | 3.40 | info | |||
Guillermo / Scandalis | 0 | 4 | 0 | ||||||||
25.02. 01:15 |
R16 | Hibi / Min | 2 | 6 | 6 | 1.23 | 3.62 | info | |||
Boren / Leon | 0 | 4 | 0 | ||||||||
25.02. 00:25 |
R16 | Kuwata / Okuno (2) | 2 | 64 | 6 | 10 | 1.83 | 1.83 | info | ||
Eraydin / Scholl | 1 | 7 | 4 | 6 | |||||||
24.02. 23:50 |
R16 | Christian / Lao | 2 | 6 | 6 | 1.43 | 2.55 | info | |||
Evtimova / Stevenson | 0 | 0 | 1 | ||||||||
24.02. 01:05 |
R16 | Pegula / Zhao (3) | 2 | 6 | 6 | 1.16 | 4.44 | info | |||
Dolehide / Shibahara | 0 | 4 | 2 | ||||||||
24.02. 00:40 |
R16 | De Vroome / Sanchez-Q | 2 | 6 | 6 | 1.51 | 2.33 | info | |||
Bektas / Lee | 0 | 4 | 4 | ||||||||
23.02. 23:55 |
R16 | Muhammad / Townsend (1) | 2 | 6 | 6 | 1.03 | 9.04 | info | |||
Facey / Facey | 0 | 0 | 1 | ||||||||
23.02. 23:55 |
R16 | Bellis / Cako | 2 | 6 | 6 | 1.71 | 1.96 | info | |||
Loeb / Weinhold (4) | 0 | 1 | 4 |
round of 16
Bektas / Lee [WC]
Loeb / Weinhold [4]
Pegula / Zhao [3]
Kuwata / Okuno [2]
quarterfinal
Pegula / Zhao [3]
Kuwata / Okuno [2]
semifinal
Pegula / Zhao [3]
final
Pegula / Zhao [3]
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