Rancho Santa Fe ITF 2014 (USA)
(25,000 $, hard, women)
Start | Round | S | 1 | 2 | 3 | 4 | 5 | H | A | ||
15.02. 19:00 |
F | Crawford / Xu (3) | 2 | 3 | 6 | 12 | 1.45 | 2.54 | info | ||
Lao / Wong | 1 | 6 | 2 | 10 | |||||||
15.02. 00:00 |
SF | Crawford / Xu (3) | 2 | 6 | 3 | 10 | 2.08 | 1.64 | info | ||
Chirico / Paszek (2) | 1 | 3 | 6 | 8 | |||||||
14.02. 22:30 |
SF | Lao / Wong | 2 | 6 | 7 | 1.84 | 1.82 | info | |||
Hesse / Zaja (4) | 0 | 4 | 5 | ||||||||
14.02. 02:20 |
QF | Chirico / Paszek (2) | 2 | 6 | 6 | 1.44 | 2.62 | info | |||
Hsu / Ishizu | 0 | 4 | 4 | ||||||||
14.02. 01:05 |
QF | Hesse / Zaja (4) | 2 | 7 | 6 | 1.32 | 3.05 | info | |||
Bellis / Higuchi | 0 | 62 | 1 | ||||||||
14.02. 00:50 |
QF | Lao / Wong | 2 | 6 | 6 | 1.92 | 1.76 | info | |||
Bhargava / Hibi | 0 | 2 | 2 | ||||||||
13.02. 23:20 |
QF | Crawford / Xu (3) | 2 | 6 | 6 | 1.53 | 2.31 | info | |||
Boserup / Peers | 0 | 3 | 1 | ||||||||
13.02. 00:10 |
R16 | Hsu / Ishizu | 2 | 7 | 6 | info | |||||
Man-Son-H / Shibahara | 0 | 62 | 3 | ||||||||
12.02. 23:50 |
R16 | Chirico / Paszek (2) | 2 | 6 | 6 | 1.13 | 5.05 | info | |||
Chalagani / Korashvil | 0 | 3 | 2 | ||||||||
12.02. 23:45 |
R16 | Hesse / Zaja (4) | 2 | 2 | 7 | 10 | 1.83 | 1.83 | info | ||
Cohen / Harkins | 1 | 6 | 610 | 5 | |||||||
12.02. 23:00 |
R16 | Lao / Wong | 1 | 2.34 | 1.52 | info | |||||
Dabrowski / Dubois (1) | 0 | ||||||||||
12.02. 22:30 |
R16 | Crawford / Xu (3) | 2 | 6 | 6 | 1.71 | 1.98 | info | |||
Marand / Weinhold | 0 | 4 | 3 | ||||||||
12.02. 22:20 |
R16 | Boserup / Peers | 2 | 6 | 2 | 10 | 1.28 | 3.50 | info | ||
Ellison / Ellison | 1 | 3 | 6 | 8 | |||||||
12.02. 22:00 |
R16 | Bhargava / Hibi | 2 | 6 | 6 | 1.12 | 5.50 | info | |||
Day / McKenzie | 0 | 1 | 2 | ||||||||
11.02. 23:55 |
R16 | Bellis / Higuchi | 2 | 6 | 6 | 2.10 | 1.66 | info | |||
Betancour / Fuentes | 0 | 4 | 2 |
round of 16
Hesse / Zaja [4]
Crawford / Xu [3]
Chirico / Paszek [2]
quarterfinal
Hesse / Zaja [4]
Crawford / Xu [3]
Chirico / Paszek [2]
semifinal
Hesse / Zaja [4]
Crawford / Xu [3]
Chirico / Paszek [2]
final
Crawford / Xu [3]
Crawford / Xu [3]
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