Grenoble challenger 2000 (France)
(75,000 $, hard, men)
Start | Round | S | 1 | 2 | 3 | 4 | 5 | H | A | ||
14.10. --:-- |
F | Knowle / Manta | 2 | 6 | 6 | info | |||||
Allegro / Cuaz | 0 | 3 | 4 | ||||||||
12.10. --:-- |
SF | Allegro / Cuaz | 2 | 7 | 3 | 6 | info | ||||
Dupuis / Llodra | 1 | 6 | 6 | 3 | |||||||
12.10. --:-- |
SF | Knowle / Manta | 2 | 6 | 6 | info | |||||
Hanley / Kerr (4) | 0 | 4 | 4 | ||||||||
11.10. --:-- |
QF | Allegro / Cuaz | 2 | 7 | 7 | info | |||||
Burgsmull / Kohlmann (1) | 0 | 5 | 6 | ||||||||
11.10. --:-- |
QF | Dupuis / Llodra | 2 | 7 | 6 | info | |||||
Bachelot / Pequery | 0 | 6 | 3 | ||||||||
11.10. --:-- |
QF | Hanley / Kerr (4) | 2 | 6 | 6 | info | |||||
Lisnard / Patience | 0 | 3 | 4 | ||||||||
11.10. --:-- |
QF | Knowle / Manta | 2 | 7 | 6 | info | |||||
Rosner / Weir-Smith (2) | 0 | 6 | 4 | ||||||||
10.10. --:-- |
R16 | Burgsmull / Kohlmann (1) | 2 | 5 | 6 | 6 | info | ||||
Lee / Trimmel | 1 | 7 | 3 | 4 | |||||||
10.10. --:-- |
R16 | Allegro / Cuaz | 2 | 5 | 6 | 6 | info | ||||
Benneteau / Mahut | 1 | 7 | 4 | 1 | |||||||
10.10. --:-- |
R16 | Bachelot / Pequery | 2 | 7 | 6 | 6 | info | ||||
Erlich / Skoch (3) | 1 | 5 | 7 | 2 | |||||||
10.10. --:-- |
R16 | Dupuis / Llodra | 2 | 7 | 7 | info | |||||
Ketola / Koves | 0 | 6 | 6 | ||||||||
10.10. --:-- |
R16 | Lisnard / Patience | 2 | 6 | 3 | 6 | info | ||||
Ascione / Maes | 1 | 4 | 6 | 3 | |||||||
10.10. --:-- |
R16 | Hanley / Kerr (4) | 2 | 6 | 7 | info | |||||
Abelson / Stepanek | 0 | 4 | 5 | ||||||||
10.10. --:-- |
R16 | Knowle / Manta | 2 | 6 | 6 | info | |||||
Faurel / Serra | 0 | 2 | 3 | ||||||||
10.10. --:-- |
R16 | Rosner / Weir-Smith (2) | 2 | 6 | 6 | info | |||||
Davidson / Delgado | 0 | 2 | 3 |
round of 16
Erlich / Skoch [3]
Hanley / Kerr [4]
quarterfinal
Hanley / Kerr [4]
semifinal
Hanley / Kerr [4]
final
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