Aschaffenburg ITF 2016 (Germany)
(25,000 $, clay, women)
| Start | Round | S | 1 | 2 | 3 | 4 | 5 | H | A | ||
| 17.07. 15:35 |
F | Geuer / Zaja | 2 | 6 | 6 | 1.89 | 1.77 | info | |||
| Jakupovic / Lu (4) | 0 | 4 | 4 | ||||||||
| 16.07. 17:30 |
SF | Jakupovic / Lu (4) | 2 | 6 | 6 | info | |||||
| Ianchuk / Kalinskay (2) | 0 | 3 | 4 | ||||||||
| 16.07. 16:30 |
SF | Geuer / Zaja | 2 | 6 | 6 | 1.48 | 2.41 | info | |||
| Arcangioli / Paquet | 0 | 4 | 2 | ||||||||
| 15.07. 16:40 |
QF | Geuer / Zaja | 2 | 6 | 6 | 2.10 | 1.66 | info | |||
| Boeykens / Lemoine (1) | 0 | 3 | 0 | ||||||||
| 15.07. 15:10 |
QF | Arcangioli / Paquet | 2 | 7 | 6 | 2.00 | 1.72 | info | |||
| Estable / Perez Roj | 0 | 5 | 3 | ||||||||
| 14.07. 17:30 |
QF | Jakupovic / Lu (4) | 2 | 6 | 6 | 1.28 | 3.23 | info | |||
| Distelman / Vogelsang | 0 | 4 | 2 | ||||||||
| 14.07. 15:55 |
QF | Ianchuk / Kalinskay (2) | 2 | 6 | 6 | info | |||||
| Brescia / Farfan | 0 | 3 | 0 | ||||||||
| 12.07. 17:30 |
R16 | Ianchuk / Kalinskay (2) | 2 | 6 | 6 | info | |||||
| Shan / Zang | 0 | 0 | 0 | ||||||||
| 12.07. 16:40 |
R16 | Estable / Perez Roj | 2 | 6 | 6 | info | |||||
| Galfi / Skamlova (3) | 0 | 4 | 4 | ||||||||
| 12.07. 16:00 |
R16 | Jakupovic / Lu (4) | 2 | 6 | 6 | 1.51 | 2.32 | info | |||
| Raina / Samir | 0 | 4 | 2 | ||||||||
| 12.07. 16:00 |
R16 | Brescia / Farfan | 2 | 6 | 6 | 1.14 | 4.68 | info | |||
| Wlodarcza / Yurtkuran | 0 | 2 | 4 | ||||||||
| 12.07. 14:45 |
R16 | Arcangioli / Paquet | 2 | 6 | 6 | 1.44 | 2.54 | info | |||
| Harris / Lahey | 0 | 1 | 1 | ||||||||
| 12.07. 14:35 |
R16 | Distelman / Vogelsang | 2 | 6 | 6 | 1.25 | 3.54 | info | |||
| Engelmann / Ladurner | 0 | 4 | 0 | ||||||||
| 12.07. 13:05 |
R16 | Boeykens / Lemoine (1) | 2 | 6 | 6 | 1.32 | 3.06 | info | |||
| Serban / Stolmar | 0 | 2 | 0 | ||||||||
| 12.07. 13:05 |
R16 | Geuer / Zaja | 2 | 6 | 6 | 1.20 | 4.17 | info | |||
| Proese / Scholl | 0 | 2 | 4 |

round of 16
Galfi / Skamlova [3]
Harris / Lahey [WC]
Jakupovic / Lu [4]
Shan / Zang [WC]
quarterfinal
Jakupovic / Lu [4]
semifinal
Jakupovic / Lu [4]
final
Jakupovic / Lu [4]
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